मराठी

Balance the following important equation: NH3 + CuO → Cu + H2O + N2

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प्रश्न

Balance the following important equation:

NH3 + CuO → Cu + H2O + N2 

एका वाक्यात उत्तर
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उत्तर

2NH3 + 3CuO → 3Cu + 3H2O + N2 

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पाठ 1: The Language of Chemistry - Additional Questions

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विराफ जे. दलाल Simplified ICSE Chemistry [English] Class 9
पाठ 1 The Language of Chemistry
Additional Questions | Q 21.32

संबंधित प्रश्‍न

Define chemical reaction.


Balance the following equation. Also name the products formed.

`CO _2 + C    →   CO`


Balance the following equation. Also name the products formed.

`PbCO _3   →  PbO +CO_2`   


Underline the incorrectly balanced compound equation and rewrite the correct equation.

\[\ce{PbO2 + 4HCl->PbCl2 + H2O + Cl2}\]


When ferrous sulphate is heated strongly it undergoes decomposition to form ferric oxide as a main product accompanied by a change in colour from:


Solid calcium oxide reacts vigorously with water to form calcium hydroxide accompanied by liberation of heat. This process is called slaking of lime. Calcium hydroxide dissolves in water to form a solution called lime water. Which among the following is (are) true about slaking of lime and the solution formed?

  1.  It is an endothermic reaction
  2.  It is an exothermic reaction
  3. The pH of the resulting solution will be more than seven
  4. The pH of the resulting solution will be less than seven

The following reaction is used for the preparation of oxygen gas in the laboratory

`2"KClO"_3("s") overset("Heat")underset("Catalyst")(->) 2"KCl"("s") + 3"O"_2 ("g")`

Which of the following statement(s) is(are) correct about the reaction ?


Write a balanced chemical equation of the following reaction and also classify them.

 Iron (III) oxide on heating with carbon monoxide gas reacts to form solid iron and liberates carbon dioxide gas.


Which of the following statement is incorrect with reference to the reaction of silver nitrate with sodium chloride?


Complete and balance the following equation:

\[\ce{C2H4Br2 + alcoholic KOH ->[\Delta]}\]


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