Advertisements
Advertisements
प्रश्न
At what rate percent will a sum of Rs 1000 amount to Rs 1102.50 in 2 years at compound interest?
Advertisements
उत्तर
\[A = P \left( 1 + \frac{R}{100} \right)^n \]
\[1102 . 50 = 1000 \left( 1 + \frac{R}{100} \right)^2 \]
\[\frac{1102 . 50}{1000} = \left( 1 + 0 . 01R \right)^2 \]
\[ \left( 1 + 0 . 01R \right)^2 = 1 . 1025\]
\[ \left( 1 + 0 . 01R \right)^2 = \left( 1 . 05 \right)^2 \]
On comparing both the sides, we get:
1 + 0.01R = 1.05
0.01R = 0.05
R = 5
Thus, the required rate percent is 5.
APPEARS IN
संबंधित प्रश्न
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years
The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.
The population of a town increases at the rate of 50 per thousand. Its population after 2 years will be 22050. Find its present population.
Jitendra set up a factory by investing Rs 2500000. During the first two successive years his profits were 5% and 10% respectively. If each year the profit was on previous year's capital, compute his total profit.
The value of a refrigerator which was purchased 2 years ago, depreciates at 12% per annum. If its present value is Rs 9680, for how much was it purchased?
A shepherd has 200 sheep with him. Find the number of sheep with him after 3 years if the increase in the number of sheep is 8% every year.
Find the compound interest if the amount of a certain principal after two years is ₹ 4036.80 at the rate of 16 p.c.p.a.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
The value of a car, bought for Rs 4,40,000 depreciates each year by 10% of its value at the beginning of that year. So its value becomes Rs 3,08,000 after three years.
