Question

At particular temperature K_c = 4 × 10^-2 for the reaction, \[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]. Calculate the K_c for the following reaction.

\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]

Answer 1

K_C = 4 x 10^-2 for the reaction

\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]

`"K"_"C" = (["H"_2]["S"_2]^(1/2))/(["H"_2"S"]) = 4 xx 10^-2`

For the reaction,

\[\ce{2H2S (g) <=> 2H2 (g) + S2 (g)}\]

`"K"_"C" = (["H"_2]^3["S"_2]^(3/2))/(["H"_2"S"]^3) = (4 xx 10^-2)^3`

= 64 × 10^-6