Advertisements
Advertisements
प्रश्न
Assume n = 10; what will be result of n++ and --n;?
Advertisements
उत्तर
11 and 9 respectively.
the notations like n++ and ++n are used in coding
both n++ and ++n stand for n=n+1 but there is small difference.
if we assume a=10 and n=10 then a<++n is true but a<n++ is false.
for a<++n first n value gets increment by 1 and becomes 11 then the condition is checked.
for a<n++ first the condition is checked and becomes false then n is incremented by 1 and becomes 11.
- -n and n- - also explained in the same way but - - is decrement operator w3here as ++ is increment operator.
APPEARS IN
संबंधित प्रश्न
Which of the following statements is not true?
Which of the following is called compile-time operators?
The following constant is of which type?
39
Write the following real constant into the exponent form:
0.00005
Describe the differences between keywords and identifiers?
Is C++ case sensitive? What is meant by the term “case sensitive”?
Differentiate “=” and “==”.
Determine which of the following are valid constant? And specify their type.
‘Name’
Determine which of the following are valid constant? And specify their type.
‘\t’
Determine which of the following are valid constant? And specify their type.
27,822
