मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Assign oxidation numbers to the underlined elements in the following species: NaBH4 - Chemistry

Advertisements
Advertisements

प्रश्न

Assign oxidation numbers to the underlined elements in the following species:

NaBH4 

संख्यात्मक
Advertisements

उत्तर

NaBH4 

+1 x -1
Na B H4

Then, we have

1(+1) + 1(x) + 4(-1) = 0

⇒ 1 + x - 4 = 0

⇒ x = + 3

Hence, the oxidation number of B is + 3.

shaalaa.com
Oxidation Number - Introduction
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

Assign oxidation numbers to the underlined element in the following species:

 NaH2PO4


Assign oxidation numbers to the underlined element in the following species:

NaHSO4


What is the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

 Fe3O4


What is the oxidation number of the underlined elements in the following and how do you rationalise your results?

CH3COOH


Consider the elements: Cs, Ne, I and F

Identify the element that exhibits only negative oxidation state.


Consider the elements: Cs, Ne, I and F.

Identify the element that exhibits only postive oxidation state.


Consider the elements : Cs, Ne, I and F

Identify the element which exhibits neither the negative nor does the positive oxidation state.


The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?


In which of the following compounds, an element exhibits two different oxidation states.


The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.

(i) 3s1

(ii) 3d14s2

(iii) 3d24s2

(iv) 3s23p3 


\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:

\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]

\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]

Why do these compounds differ in their reactivity?


Nitric acid is an oxidising agent and reacts with \[\ce{PbO}\] but it does not react with \[\ce{PbO2}\]. Explain why?


Calculate the oxidation number of phosphorus in the following species.

\[\ce{PO^{3-}4}\]


Calculate the oxidation number of sulphur atom in the following compounds:

\[\ce{Na2S2O3}\]


Calculate the oxidation number of sulphur atom in the following compounds:

\[\ce{Na2S4O6}\]


Match Column I with Column II for the oxidation states of the central atoms.

Column I Column II
(i) \[\ce{Cr2O^{2-}7}\] (a) + 3
(ii) \[\ce{MnO^{-}4}\] (b) + 4
(iii) \[\ce{VO^{-}3}\] (c) + 5
(iv) \[\ce{FeF^{3-}6}\] (d) + 6
  (e) + 7

The oxidation number of P in Mg2P207 is ____________. 


On reaction with a stronger oxidizing agent like KIO4, hydrogen peroxide with the evolution of O2. The oxidation number of I in KIO4 changes to ______.


Oxidation state of sulphur in anions `"SO"_3^(2-)`, `"S"_2"O"_4^(2-)` and `"S"_2"O"_6^(2-)` increases in the orders:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×