मराठी

Assertion (A): The nth term of a G.P. is given by $$T_{n} = ar^{n - 1}$$. Reason (R): A sequence $$a_{1}, a_{2}, a_{3} ....$$ is said to a G.P. if $$\frac{a_{1}}{a_{2}} = \frac{a_{2}}{a_{3}}

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प्रश्न

Assertion (A): The nth term of a G.P. is given by $$T_{n} = ar^{n - 1}$$. 

Reason (R): A sequence $$a_{1}, a_{2}, a_{3} ....$$ is said to a G.P. if $$\frac{a_{1}}{a_{2}} = \frac{a_{2}}{a_{3}} = \frac{a_{3}}{a_{4}} ....$$ = constant known as the common ratio.

पर्याय

  • Both A and R are true, and R is the correct explanation of A.

  • Both A and R are true, but R is not the correct explanation of A.

  • A is true, but R is false.

  • A is false, but R is true.

MCQ
विधान आणि तर्क
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उत्तर

A is true, but R is false.

Explanation:

The assertion is true: the general term of a G.P. is $$T_n = ar^{n - 1}$$. The reason is false because the common ratio is $$\frac{a_2}{a_1} = \frac{a_3}{a_2} = \cdots = r$$, while $$\frac{a_1}{a_2}, \frac{a_2}{a_3}, \cdots$$ are its reciprocals, not the common ratio.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Geometric Progression - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ १८३]

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आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 11 Geometric Progression
COMPETENCY-FOCUSED QUESTIONS | Q 1. | पृष्ठ १८३
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