मराठी

Assertion (A): If $$8 < 5(x + 1) - 2 \leq 18,\ x\in\mathrm{R}$$, then the smallest integer value of $$x$$ is 0. Reason (R): Multiplying each side of an inequation by the same integer

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प्रश्न

Assertion (A): If $$8 < 5(x + 1) - 2 \leq 18,\ x\in\mathrm{R}$$, then the smallest integer value of $$x$$ is 0.

Reason (R): Multiplying each side of an inequation by the same integer does not change the inequality.

पर्याय

  • Both A and R are true, and R is the correct explanation of A.

  • Both A and R are true, but R is not the correct explanation of A.

  • A is true, but R is false.

  • A is false, but R is true.

MCQ
विधान आणि तर्क
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उत्तर

A is false, but R is true.

Explanation:

Step 1 – Assertion: A is false. $$8 < 5(x + 1) - 2 \le 18$$ $$8 < 5x + 5 - 2 \le 18$$ $$8 < 5x + 3 \le 18$$ $$8 - 3 < 5x \le 18 - 3$$ $$5 < 5x \le 15$$ $$1 < x \le 3$$ Since $$x \in \mathrm{R}$$, the integer values of $$x$$ satisfying the inequation are 2 and 3. Therefore, the smallest integer value of $$x$$ is 2, not 0.

Step 2 – Reason: R is true. Multiplying each side of an inequation by the same positive integer does not change the inequality.

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पाठ 4: Linear Inequations - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ ४८]

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आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 4 Linear Inequations
COMPETENCY-FOCUSED QUESTIONS | Q 1. | पृष्ठ ४८
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