मराठी

Assertion (A): For an A.P., (\mathrm{T}_{22} = 149) and (d = 7). Then (\mathrm{S}{22}) is 1661. Reason (R): The sum of first (n) terms of an A.P. is given by (\mathrm{S}_{n} = \frac{n}{2}

Advertisements
Advertisements

प्रश्न

Assertion (A): For an A.P., \(\mathrm{T}_{22} = 149\) and \(d = 7\). Then \(\mathrm{S}_{22}\) is 1661.

Reason (R): The sum of first n terms of an A.P. is given by \(\mathrm{S}_{n} = \frac{n}{2}[2a - (n - 1)d]\).

पर्याय

  • Both A and R are true, and R is the correct explanation of A.

  • Both A and R are true, but R is not the correct explanation of A.

  • A is true, but R is false.

  • A is false, but R is true.

MCQ
विधान आणि तर्क
Advertisements

उत्तर

A is true, but R is false.

Explanation:

Assertion: \(a + 21(7) = 149 \Rightarrow a = 2\), and \(S_{22} = \frac{22}{2}[2(2) + 21(7)] = 11(151) = 1661\). Hence A is true. 

Reason: The correct formula is \(\mathrm{S}_{n} = \frac{n}{2}[2a + (n - 1)d]\) with a plus sign; the reason has a minus sign, so R is false.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Arithmetic Progression - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ १७१]

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 10 Arithmetic Progression
COMPETENCY-FOCUSED QUESTIONS | Q 3. | पृष्ठ १७१
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×