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प्रश्न
Arrange the following in the increasing order of their boiling point and give a reason for your ordering.
Propan-1-ol, propan-1, 2, 3-triol, propan-1, 3-diol, propan-2-ol
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उत्तर
2° alcohols have lower boiling points than 1° alcohol due to a corresponding decrease in the extent of H-bonding because of steric hindrance. Therefore Propan-1-ol has a higher boiling point than Propan-2-ol. Hydrogen group increases, boiling point also increases. Overall increasing order of boiling points is, propan-2-ol < Propan-1-ol < propan-1, 3-diol < propan-1, 2, 3-triol.
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\[\begin{array}{cc}
\ce{CH3}\phantom{......}\\
|\phantom{........}\\
\ce{H3C - CH - CH - CH - CH2 - OH}\\
|\phantom{............}|\phantom{........}\\
\ce{Cl}\phantom{...........}\ce{CH3}\phantom{......}
\end{array}\]
