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प्रश्न
Answer the following:
Find the trigonometric functions of :
−180°
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उत्तर
Trigonometric Functions of (−180°) :
Let m∠XOA = (−180°)
Its terminal arm (ray OA) intersects the standard unit circle at P(– 1, 0).
∴ x = – 1 and y = 0
sin (−180°) = y = 0
cos (−180°) = x = – 1
tan (−180°) = `y/x`
= `0/(-1)`
= 0
cosec (−180°) = `1/y`
= `1/0`, which is not defined
sec (−180°) = `1/x = 1/(-1)` = – 1
cot (−180°) = `x/y = (-1)/0`, which is not defined.
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