Question

An object at an angle such that the horizontal range is 4 times the maximum height. What is the angle of projection of the object?

Answer 1

Given,

Horizontal range = 4H_max

Solution:

Horizontal range = `(u^2 sin2theta)/g = (2u^2 sintheta costheta)/g`

Maximum height = `(u^2 sin^2theta)/(2g)`

as given `(2u^2 sin theta costheta)/g = (4u^2 sin^2theta)/(2g)`

2 cosθ = 2 sinθ

tanθ = 1

∴ θ = 45°