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प्रश्न
An isosceles triangle ABC is inscribed in a circle when AB = AC = 20 cm and BC = 24 cm. Find the radius of the circle.
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उत्तर
Given:
- The triangle ABC is isosceles with AB = AC = 20 cm and BC = 24 cm.
- We need to find the radius of the circumcircle.
Step 1: Use the formula for the circumradius
The formula for the circumradius R of a triangle is given by:
`R = (abc)/(4A)`
Where:
- a, b, c are the sides of the triangle,
- A is the area of the triangle.
In our case:
- a = 20 cm (side AB),
- b = 20 cm (side AC),
- c = 24 cm (side BC).
We first need to find the area A of the triangle.
Step 2: Find the area of the triangle using Heron's formula
The semi-perimeter s of the triangle is:
`s = (a + b + c)/2`
= `(20 + 20 + 24)/2`
= 32 cm
Now, using Heron’s formula to find the area A:
`A = sqrt(s(s - a)(s - b)(s - c))`
Substitute the values:
`A = sqrt(32(32 - 30)(32 - 20)(32 - 24))`
`A = sqrt(32 xx 12 xx 12 xx 8)`
`A = sqrt(36864)`
A = 192 cm2
Step 3: Calculate the circumradius
Now that we have the area, we can use the circumradius formula:
`R = (abc)/(4A)`
= `(20 xx 20 xx 24)/(4 xx 192)`
`R = 9600/768`
R = 12.5 cm
The radius of the circle is 12.5 cm.
