Question

An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

Answer 1

Let the number of electrons present in ion `"A"^(3+)`  be  x

∴ Number of neutrons in it = x + 30.4% of x = 1.304 x

Since the ion is tripositive,

⇒ Number of electrons in neutral atom = x + 3

∴ Number of protons in neutral atom = x + 3

Given,

Mass number of the ion = 56

`therefore (x + 3) + (1.304 x) = 56`

2.304 x = 53 

`x = 53/2.304`

x = 23

∴ Number of protons = x + 3 = 23 + 3 = 26

∴ The symbol of the ion `""_26^56"Fe"^(3+)`