Question

An ideal gas is taken through a cycle thermodynamic process through four steps. The amounts of heat involved in these steps are Q₁ = 5960 J, Q₂ = −5585 J, Q₃ = −2980 J, Q₄ = 3645 J, respectively. The corresponding works involved are W₁ = 2200 J, W₂ = −825 J, W₃ = −1100 J, and W₄ respectively, the value of W₄ is:

पर्याय

• 780

• 775

• 765

• 760

Answer 1

765

Explanation:

For the cyclic process ΔU = ‘0’

According to I^st law of thermodynamics

W = ΔQ

2200 − 825 − 1100 + W₄ = 5960 − 5585 − 2980 + 3645

W₄ = 765 J