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प्रश्न
An erect image 2.0 cm high is formed 12 cm from a lens, the object being 0.5 cm high. Find the focal length of the lens.
संख्यात्मक
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उत्तर
Given:
Image distance, v = −12 cm (Image is erect.)
Height of the object, h = 0.5 cm
Height of the image, h' = 2.0 cm
Applying the magnification formula, we get:
m = `v/u = (h')/h`
`-12/u = 2.0/0.5`
u = −3 cm
Applying the lens formula, we get:
`1/v- 1/u = 1/f`
`1/(-12)-1/(-3) = 1/f`
`1/f = 3/12`
f = 4.0 cm
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