Advertisements
Advertisements
प्रश्न
An engine does 54,000 J of work by exerting a force of 6000 N on it. What is the displacement in the direction of the force?
Advertisements
उत्तर
Given work done = 54,000J, force = 6000 N, 0 = 0°
Now work done = force x displacement x cos 0°
or displacement = `54000/6000` = 9m
APPEARS IN
संबंधित प्रश्न
A man spends 7.4 KJ energy in displacing a body by 74 m in the direction in which he applies force in 2.5 s. Calculate the force applied.
The moment of a force 10 N about a point 0 is 4 Nm. Calculate the distance of point of application of force from the point 0.
Work is a scalar quantity because it is a measure of transfer of energy without indicating any direction
It takes 20 s for a person A of mass 50 kg to climb up the stairs, while another person B of same mass does the same in 15 s. Compare the power developed by the persons A and B.
What is the work done by the gravitational force on the moon that revolves around the earth?
What is the S.I. unit of work? Define it.
State the S.I. and C.G.S. units of energy. How are they related?
A machine raises a load of 750 N through a height of 16 m in 5 seconds. Calculate the power at which the machine works.
State the C.G.S. unit of work. How it is related to its S.I. unit?
A boy weighing 50 kgf climbs up from the first floor at a height of 3 m above the ground to the third floor at a height of 9 m above the ground. What will be the increase in his gravitational potential energy? (Take g = 10 N kg-1).
