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An electron moving along the positive X axis with a velocity of 8 × 107 ms−1 enters a region having a uniform magnetic field B = 1.3 × 10^−3 T along the positive Y axis. - Physics (Theory)

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प्रश्न

An electron moving along the positive X axis with a velocity of 8 × 107 ms−1 enters a region having a uniform magnetic field B = 1.3 × 103 T along the positive Y axis.

  1. Explain why the electron describes a circular path.
  2. Calculate the radius of the circular path described by the electron.
स्पष्ट करा
संख्यात्मक
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उत्तर

a. Because the force exerted by the magnetic field is always perpendicular to the velocity of the electron. Hence, it provides the necessary centripetal force and the electron describes a circular path.

b. Magnetic force = Centripetal force

evB = `"mv"^2/r`

⇒ `e/m = v/(Br)`

`(1.6 xx 10^(-19))/(9.1 xx 10^(-31)) = (8 xx 10^7)/(1.3 xx 10^(-3) xx r)`

∴ r = 0.35 m

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