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प्रश्न
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, ______.
(nearly) (me= 9 x 10-31 kg)
पर्याय
12.2 x 10-14 m
12.2 nm
12.2 x 10-13 m
12.2 x 10-12 m
MCQ
रिकाम्या जागा भरा
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उत्तर
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, ______.
Explanation:
de Broglie wavelength,
`lambda = 12.27/ sqrt("V" ("in volts")`
= `12.27/ sqrt10000` Å
≈ `12.2 xx 10-12 m
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Types of Waves
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