Question

An electron and a proton are moving along the +X axis. If an external magnetic field B = 0.314 T is applied along −Z axis:

1. What is the path followed by the electron due to the magnetic field?
2. Calculate the frequency of revolution of the proton.

Answer 1

a. The path followed by the electron is circular.

b. Frequency of the revolving proton is,

F = `(qB)/(2 pi m)`

= `(1.6 xx 10^-19 xx 0.314)/(2 xx 3.14 xx 1.67 xx 10^-27)` Hz

= 4.79 × 10⁶ Hz