Question

An electric bulb is rated 500 W-250 V. The magnitude of the current of such a bulb is:

पर्याय

• 2.2 A

• 2 A

• 2.4 A

• none of these

Answer 1

2 A

Explanation:

$$P = VI$$

$$I = \frac{P}{V}$$

$$= \frac{500}{250}$$

= 2 A