Question

An architecture have model of building. Length of building is 1 m then length of model is 0.75 cm. Then find length and height of model building whose actual length is 22.5 m and height is 10 m

Answer 1

Rough Figure -

Actual length/height	Model length/height
1 m	0.75 cm
22.5 m	? (x cm)
10 m	? (y cm)

The actual length of 1 m is shown as 0.75 cm in the model then let the actual length of 22.5 m is shown in the model by 'x' cm.

`therefore 1/22.5 = 0.75/x`

∴ x = `0.75 xx 22.5`

x = 16.875 cm

Now, The actual length of 1 m is shown as 0.75 cm in the model then let the actual height of 10 m is shown in the model by 'y' cm.

`therefore 1/10 = 0.75/"y"`

∴ y = 0.75 × 10

y = 7.5 cm