Advertisements
Advertisements
प्रश्न
Add: x2 - y2 - 1 , y2 - 1 - x2, 1- x2 - y2
Advertisements
उत्तर
(x2 - y2 - 1) + (y2 - 1 - x2) + (1 - x2 - y2)
= x2 - y2 - 1 + y2 - 1 - x2 + 1 - x2 - y2
= x2 - x2 - x2 − y2 + y2 - y2 - 1 - 1 + 1
= x2(1 - 1 - 1) + y2 (-1 + 1 - 1) + (- 1 - 1 + 1)
= -x2 - y2 - 1
संबंधित प्रश्न
Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz.
Simplify combining like terms: p − (p − q) − q − (q − p)
Simplify combining like terms: 5x2y − 5x2 + 3y x2 − 3y2 + x2 − y2 + 8xy2 −3y2
Simplify combining like terms: (3y2 + 5y - 4) - (8y - y2 - 4)
What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?
From the sum of 3x - y + 11 and - y - 11, subtract 3x - y - 11.
Add the following algebraic expression:
\[\frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x, - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
Subtract:
2a2 from − 7a2
Add: 2a + b + 3c and `"a" + 1/3"b" + 2/5"c"`
Sum of x and y is x + y.
