Advertisements
Advertisements
प्रश्न
Add the following expressions:
a2 + 3ab – bc, b2 + 3bc – ca and c2 + 3ca – ab
Advertisements
उत्तर
We have, (a2 + 3ab – bc) + (b2 + 3bc – ca) + (c2 + 3ca – ab)
On combining the like terms,
= a2 + 3b – bc + b2 + 3bc – ca + c2 + 3ca – ab
= a2 + b2 + c2 + 3ab – ab – 3bc – ca + 3ca
= a2 + b2 + c2 + 2ab + 2bc + 2ca
APPEARS IN
संबंधित प्रश्न
Add: 3p2q2 - 4pq + 5, - 10p2q2, 15 + 9pq + 7p2q2
Subtract: 6xy from − 12xy
From the sum of 4 + 3x and 5 - 4x + 2x2, subtract the sum of 3x2 - 5x and -x2 + 2x + 5.
Subtract:
− 5xy from 12xy
Add:
−3y2 + 10y − 16; 7y2 + 8
Solve:
(6a − 5b − 8c) + (15b + 2a − 5c)
If x is a natural number, then x + 1 is its predecessor
Find the sum of the following expressions
7p + 6q, 5p – q, q + 16p
Add:
5x2 – 3xy + 4y2 – 9, 7y2 + 5xy – 2x2 + 13
Each symbol given below represents an algebraic expression:
= 2x2 + 3y,
= 5x2 + 3x,
= 8y2 – 3x2 + 2x + 3y
The symbols are then represented in the expression:

Find the expression which is represented by the above symbols.
