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प्रश्न
AD is a median of ΔABC with vertices A (5, -6), B (6, 4) and C (0, 0). Length AD is equal to ______.
पर्याय
`sqrt68` units
`2sqrt15` units
`sqrt101` units
10 units
MCQ
रिकाम्या जागा भरा
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उत्तर
AD is a median of ΔABC with vertices A (5, -6), B (6, 4) and C (0, 0). Length AD is equal to `underlinebb(sqrt68 "units")`.
Explanation:
Coordinates of D(x, y).
Using the mid-point formula, the coordinates of the midpoint of BC are
Co-ordinates of D(x, y) = `((6 + 0)/2, (4 + 0)/2)`
= (3, 2)
Now, length of AD = `sqrt((x_4-x_1)^2+(y_4-y_1)^2)`
= `sqrt((3 - 5)^2 + (2 + 6)^2)`
= `sqrt(4 + 64)`
= `sqrt68` units
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