Question

`abx^2+(b^2-ac)x-bc=0` 

Answer 1

`abx^2+(b^2-ac)x-bc=0` 

⇒`abx^2+b^2x-acx-bc=0` 

⇒`bx(ax+b)-c(ax+b)=0` 

⇒`(bx-c)(ax+b)=0` 

⇒`bx-c=0  or  ax+b=0` 

⇒`x=c/b  or  x=-b/a` 

Hence, the roots of the equation are `c/b ` and `-b/a`