Question

∆ABC is an isosceles triangle in which ∠C = 90. If AC = 6 cm, then AB = 

पर्याय

• \[6\sqrt{2} cm\]

• 6 cm

• \[2\sqrt{6} cm\]
• \[4\sqrt{2} cm\]

Answer 1

Given: In an isosceles ΔABC, `∠C= 90^o`, AC = 6 cm.

To find: AB

In an isosceles ΔABC, `∠C= 90^o`,.

Therefore, BC = AC = 6 cm

Applying Pythagoras theorem in ΔABC, we get

`AB^2=AC^2+BC^2`

`AB^2=6^2+6^2(AC=BC)`(Side of isosceles triangle)

`AB^2=36+36`

`AB^2=72`

`AB= 6sqrt2 cm`

We got the result as `a`.