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प्रश्न
ABC is an isosceles triangle such that AB = AC and AD is the median to base BC. Then, ∠BAD =
पर्याय
55°
70°
35°
110°
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उत्तर
It is given that ∠B = 35°, AB=AC and Ad is the median of BC
We know that in isosceles triangle the median from he vertex to the unequal side divides it into two equal part at right angle.
Therefore,
∠ADB = 90°
∠B = ∠ADB + ∠A= 180° (Property of triangle)
35° + 90° +∠A = 180°
∠A = 180° - 125°
∠A = 55°
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