Question

ABC is a triangle whose vertices are A(1, –1), B(0, 4) and C(–6, 4). D is the midpoint of BC. Find the co-ordinates of D.

Answer 1

$$D$$ is the mid-point of $$BC$$ where $$B(0, 4)$$ and $$C(-6, 4)$$.

$$D = \left(\frac{0 + (-6)}{2}, \frac{4 + 4}{2}\right)$$

$$= \left(-3, \frac{8}{2}\right)$$

$$= (-3, 4)$$