Advertisements
Advertisements
प्रश्न
A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 84 kg?
Advertisements
उत्तर
Let the reduced weight be x.
Original weight = 84kg
Thus, we have
84 : x = 7 : 5
⇒ `84/"x" = 7/5`
⇒ 84 x 5 = 7 x x
⇒ x = `(84 xx 5)/7`
⇒ x = 60
Thus, her reduced weight is 60 kg.
संबंधित प्रश्न
If (3a + 2b) : (5a + 3b) = 18 : 29. Find a : b
If 3A = 4B = 6C, find: A : B : C.
Find the compounded ratio of the following:
`sqrt 8 : 4 , 3 : sqrt 5` and `sqrt 20 : sqrt 27`
If (5x+3) : (3x+ 1) is the triplicate ratio of 4 : 3 , find x.
If `(3x + 5y)/(3x - 5y) = (7)/(3)` , Find x : y
In an examination, the ratio of passes to failures was 4 : 1. If 30 less had appeared and 20 less passed, the ratio of passes to failures would have been 5 : 1. How many students appeared for the examination
If a : b = 9 : 10, find the value of `(2a^2 - 3b^2)/(2a^2 + 3b^2)`
See the figure and find the ratio of number of circles to all the figures inside the rectangle.

Express 150% as a ratio in the lowest form.
If A : B = 7 : 5 and B : C = 7 : 5, then A : C is ______.
