Advertisements
Advertisements
प्रश्न
A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 84 kg?
Advertisements
उत्तर
Let the reduced weight be x.
Original weight = 84kg
Thus, we have
84 : x = 7 : 5
⇒ `84/"x" = 7/5`
⇒ 84 x 5 = 7 x x
⇒ x = `(84 xx 5)/7`
⇒ x = 60
Thus, her reduced weight is 60 kg.
संबंधित प्रश्न
if `x/a = y/b = z/c` prove that `(ax - by)/((a + b)(x - y)) + (by - cz)/((b + c)(y - z)) + (cz - az)/((c + a)(z - x)) = 3`
If (x + 3) : (4x + 1) is the duplicate ratio of 3 : 5, find the value of x.
The ratio between two numbers is 3: 4. If their L.C.M., is 180. Find the numbers.
If x : y − 5 : 4 and 2 : x = 3 : 8, find the value of y.
Rohit goes to school by car at 60 km per hour and Manoj goes to school by scooty at 40 km per hour. If they both live in the same locality, find the ratio between the time taken by Rohit and Manoj to reach school.
If x, y, and z are in continued proportion, then which of the following is true:
y : x = y : z
Find the third proportional to 5.25, 7
Find the ratio of the first quantity to the second.
1 litre, 250 ml
A certain sum was divided among A, B and C in the ratio 7 : 5 : 4. If B got Rs 500 more than C, find the total sum divided.
The number of milk teeth in human beings is 20 and the number of permanent teeth is 32. Find the ratio of the number of milk teeth to the number of permanent teeth.
