Advertisements
Advertisements
प्रश्न
A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 84 kg?
Advertisements
उत्तर
Let the reduced weight be x.
Original weight = 84 kg
Thus, we have
84 : x = 7 : 5
`=> 84/x = 7/5`
`=> 84 xx 5 = 7 xx x`
`=> x = (84 xx 5)/7`
`=>` x = 60
Thus, her reduced weight is 60 kg.
APPEARS IN
संबंधित प्रश्न
Find sub-triplicate ratio of 64 : 27
Find the compounded ratio of the following:
3 : 5, 7 : 9 and 15 : 28
Two numbers are in the ratio 7 : 10. If 8 is added to each number, the ratio becomes 3 : 4. Find the nLimbers.
If 3x – 2y – 7z = 0 and 2x + 3y – 5z = 0 find x : y : z.
In winter, a school opens at 10 a.m. and closes at 3.30 p.m. If the lunch interval is of 30 minutes, find the ratio of lunch interval to total lime of the class periods.
In the example below, find the ratio of the first number to the second.
52, 65
Find the sub-triplicate ratio of 1 : 216
If `x/a = y/b = z/c`, prove that `(3x^3 - 5y^3 + 4z^3)/(3a^3 - 5b^3 + 4c^3) = ((3x - 5y + 4z)/(3a - 5b + 4c))^3`.
The ratio 4 : 16 is in its lowest form.
There are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.
