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प्रश्न
|
A wall mounted lamp, made of fabric, is shown below. Lamp has cuboidal shape, open from top and bottom. A spherical bulb of diameter 7 cm is latched with a very thin rod. (Ignore the rod while making calculations.)
Dimensions of the cuboid are 24 cm × 12 cm × 17 cm. |
(i) Find the surface area of the bulb. [1]
(ii) What could be the maximum diameter of the bulb if at least 1 cm space is left from each side? [1]
(iii) (a) Find the area of the fabric used ifthere is a fold of 2 cm on top and bottom edges. [2]
OR
(iii) (b) Find the space available inside the lamp. [2]
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उत्तर
(i) Surface area of bulb = 4πr2
= `4 xx 22/7 xx 7/2 xx 7/2` ...[d = 7]
= 22 × 7
= 154 cm2
(ii) Internal dimension 24 × 12 × 17
Length = 24 – (1 cm + 1 cm) = 22 cm
Width = 12 – (1 cm + 1 cm) = 10 cm
Height = 17 – (1 cm + 1 cm) = 15 cm
Maximum diameter = Minimum of (22 cm, 10 cm, 15 cm) = 10 cm
(iii) (a) Required height = 17 cm + 2 cm + 2 cm = 21 cm
Fabric required = 2(l + b) × h
Area of 4 walls = 2(24 + 12) × 21
= 72 × 21
= 1512 cm2
OR
(iii) (b) Space available = l × b × h
Volume = 24 × 12 × 17
= 4896 cm3


