Advertisements
Advertisements
प्रश्न
A two digit number is four times the sum and 3 times the product of its digits, find the number.
Advertisements
उत्तर
Let this two digit number be 'Xi. Which means X=10x (as it comes in tens digit).
Then as per the question,
XY = 4 (X + Y)
⇒ 4(X+Y) = 10 X+ Y ..... (i)
and XY= 3(XY)= 10X + Y ..... (ii)
From (i), we get, 6X = 3Y
⇒ X = `"Y"/2`
Putting this in (ii) , we get : `(10 "Y")/2 + "Y" = (3 "Y")/2 xx "Y"`
`5"Y" + "Y" = 3/2 "Y"^2`
⇒ Solving this we get: 3Y2=12Y
⇒ Y = 4
Hence X = `"Y"/2 = 2`
Hence , number is 24.
APPEARS IN
संबंधित प्रश्न
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Solve the following quadratic equations by factorization:
x2 + 2ab = (2a + b)x
A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also, find the solution of the equation:
x2 – (m + 2)x + (m + 5) = 0
`8x^2-14x-15=0`
Divide 57 into two parts whose product is 680.
If the equation ax2 + 2x + a = 0 has two distinct roots, if
Solve the following equation: `"a"/("x" - "a") + "b"/("x" - "b") = (2"c")/("x" - "c")`
Solve the following equation by factorization
`x + (1)/x = 2(1)/(20)`
The hotel bill for a number of people for an overnight stay is Rs. 4800. If there were 4 more, the bill each person had to pay would have reduced by Rs. 200. Find the number of people staying overnight.
