मराठी

A train is travelling at a speed of 90 km h−1. Brakes are applied so as to produce a uniform acceleration of −0.5 m s−2. Find how far the train will go before it is brought to rest. - Science

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प्रश्न

A train is travelling at a speed of 90 km h−1. Brakes are applied so as to produce a uniform acceleration of −0.5 m s−2. Find how far the train will go before it is brought to rest.

बेरीज
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उत्तर

Initial velocity of train (u) = 90 km h−1

= `(90 xx 1000)/3600`

= 25 m/s

Final velocity due to rest (v) = 0

Acceleration (a) = −0.5 ms−2

Third equation of motion

v2 = u2 + 2as

0 = 252 + 2 (−0.5) × s

s = 625 m

Therefore, distance covered before coming to rest = 625 m

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पाठ 7: Motion - Intext question [पृष्ठ ८२]

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एनसीईआरटी Science [English] Class 9
पाठ 7 Motion
Intext question | Q 17. | पृष्ठ ८२
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