Question

A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 600. What is the height of the tower?

Answer 1

Let AC be the ladder of length, hm and C be the points, makes an angle of elevation 60° with the wall and foot of the ladder is 9.5 meters away from the wall.

In a triangle ABC, given that BC = 9.5 m and angle C = 60°

Now we have to find the length of the ladder.

So we use trigonometrically ratios.

In a triangle ABC,

`=> cos C = (BC)/(AC)`

`=>  cos 60^@ = 9.5/h`

`=> 1/2 = 9.5/h`

`=> h = 19`

Hence length of ladder is 19 meters