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प्रश्न
Answer the following questions:
A time period of a particle in SHM depends on the force constant k and mass m of the particle: `T = 2pi sqrt(m/k)` A simple pendulum executes SHM approximately. Why then is the time
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उत्तर १
The time period of a simple pendulum, `T = 2pi sqrt(m/k)`
For a simple pendulum, k is expressed in terms of mass m, as: `k prop m`
`m/k =` Constant
Hence, the time period T, of a simple pendulum is independent of the mass of the bob.
उत्तर २
In case of a spring, k does not depend upon m. However, in case of a simple pendulum, k is directly proportional to m and hence the ratio m/k is constant quantity
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संबंधित प्रश्न
let us take the position of mass when the spring is unstretched as x = 0, and the direction from left to right as the positive direction of the x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is
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