Advertisements
Advertisements
प्रश्न
A thin metal plate is placed against the teeth of cog wheel. Cog wheel is rotated at a speed of 120 rotations per minute and has 160 teeth. Calculate:
- frequency of node produced.
- speed of sound, if wavelength is 1.05 m.
- what will be the effect when the speed of cog wheel is doubled?
Advertisements
उत्तर
Frequency for rotation of wheel = 120 rotations per minute
f = `120/60` rotation per second
f = 2 rotations per second
Number of teeth on the wheel = n = 160
(i) Frequency of nod = nf
f = 160 × 2
f = 320 Hz
(ii) Wavelength = λ = 1.05 m
Speed of sound = v = ?
v = λf
v = 1.05 × 320
v = 336 ms-1
(iii) When speed of cog wheel is doubled, then frequency of nod increases and hence sound becomes shrill.
APPEARS IN
संबंधित प्रश्न
Write the audible range of frequency for the normal human ear.
When we change a feeble sound to a loud sound, we increase its :
In fig. shows a snap shot of a wave from of frequency 50 Hz in a string. The numbers in the diagram represents distance in centimeters. Fpr the wave motion, find
(a) Wavelength,
(b) Amplitude,
(c) Velocity.
A continuous disturbance is created on the surface of water in a ripple tank with a small piece of cork floating on it. Describe the motion of the cork. What does the motion of the cork tell about the disturbance?
The diagram given below shows a displacement distance graph of a wave. If the velocity of wave is 160 ms-1, calculate:
- wavelength
- frequency
- amplitude.
State the effect of pressure on the speed of sound in air.
What do you mean by an echo?
Why does an empty vessel produce more sound than a filled one?
