Advertisements
Advertisements
प्रश्न
A table top is semicircular in shape with diameter 2.8 m. Area of this table top is ______.
पर्याय
3.08 m2
6.16 m2
12.32 m2
24.64 m2
Advertisements
उत्तर
A table top is semicircular in shape with diameter 2.8 m. Area of this table top is `bb(underline(3.08 m^2))`.
Explanation:
From the question it is given that, diameter of semicircular shape = 2.8 m
So, radius of semicircular shape = `2.8/2` = 1.4 m
Then, area of semicircular shape of tablet top = `(πr^2)/2`
= `((22/7) xx 1.4 xx 1.4)/2`
= 3.08 m2
APPEARS IN
संबंधित प्रश्न
A 80 m by 64 m rectangular lawn has two roads, each 5 m wide, running through its middle, one parallel to its length and the other parallel to its breadth. Find the cost of gravelling the reads at ₹` 40 per m^2`
Find the area of the quadrilateral ABCD in which AD = 24 cm, ∠BAD 90° and ∠BCD is an equilateral triangle having each side equal to 26 cm. Also, find the perimeter of the quadrilateral.
In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find the length of the arc. (Use π = `22/7`)
In the following figure, ABCD is a rectangle, having AB = 20 cm and BC = 14 cm. Two sectors of 180° have been cut off. Calculate:
the length of the boundary of the shaded region.
In the following figure a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 21 cm, find the area of the shaded region.
In the given figure, ABCD is a trapezium with AB || DC, AB = 18 cm DC = 32 cm and the distance between AB and DC is 14 cm. Circles of equal radii 7 cm with centres A, B, C and D have been drawn. Then find the area of the shaded region.
(Use \[\pi = \frac{22}{7}\]
The area of the largest triangle that can be inscribed in a semi-circle of radius r, is
On decreasing the radius of a circle by 30%, its area is decreased by
A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, π = 3.14) is
Find the area enclosed between two concentric circles, If their radii are 6cm and 13cm respectively.
