Advertisements
Advertisements
प्रश्न
A sum of Rs. 700 is to be paid to give seven cash prizes to the students of a school for their overall academic performance. If the cost of each prize is Rs. 20 less than its preceding prize; find the value of each of the prizes.
Advertisements
उत्तर
Total amount of Prize Sn = Rs. 700
Let the value of the first prize be Rs. a
Number of prizes = n = 7
Let the value of first prize be Rs. a
Depreciation in next prize = Rs. 20
We have,
`S_n = n/2 [2a + (n - 1)d]`
`\implies 700 = 7/2 [2a + 6(-20)]`
`\implies 700 = 7/2 [2a = 120]`
`\implies` 1400 = 14a – 840
`\implies` 14a = 2240
`\implies` a = 160
`\implies` Value of 1st Prize = Rs. 160
Value of 2nd Prize = Rs. (160 – 20) Rs. 140
Value of 3rd Prize = Rs. (140 – 20) = Rs. 120
Value of 4th Prize = Rs. (120 – 20) = Rs. 100
Value of 5th Prize = Rs. (100 – 20) Rs. 80
Value of 6th Prize = Rs. (80 – 20) = Rs. 60
Value of 7th Prize = Rs. (60 – 20) = Rs. 40
संबंधित प्रश्न
The first and the last terms of an AP are 8 and 65 respectively. If the sum of all its terms is 730, find its common difference.
The ratio of the sum use of n terms of two A.P.’s is (7n + 1) : (4n + 27). Find the ratio of their mth terms
Find the sum of first 12 natural numbers each of which is a multiple of 7.
The fourth term of an A.P. is 11 and the eighth term exceeds twice the fourth term by 5. Find the A.P. and the sum of first 50 terms.
In an A.P. sum of three consecutive terms is 27 and their product is 504, find the terms.
(Assume that three consecutive terms in A.P. are a – d, a, a + d).
In an A.P., if Sn = n(4n + 1), find the A.P.
Find the value of a25 – a15 for the AP: 6, 9, 12, 15, ………..
The sum of A.P. 4, 7, 10, 13, ........ upto 20 terms is ______.
The sum of 40 terms of the A.P. 7 + 10 + 13 + 16 + .......... is ______.
When the first term a, the number of terms n and the last term l are known, which formula gives the sum of the first n terms of an Arithmetic Progression?
