Question

A stone placed at the bottom of a swimming tank appears raised by 1.5 m. If the refractive index of water is 1.33, the actual depth of swimming tank is:

पर्याय

• 5.90 m

• 5.95 m

• 6.00 m

• 6.10 m

Answer 1

6.00 m

Explanation:

The apparent rise is the real depth minus the apparent depth.

Using $$\mu=\frac{\text{real depth}}{\text{apparent depth}}$$ and a rise of $$1.5\ \mathrm{m}$$ gives a real depth of approximately $$6.0\ \mathrm{m}.$$