Advertisements
Advertisements
प्रश्न
A sound wavelength of 0.332 m has a time period of 10−3 s. If the time period is decreased to 10−4 s, calculate the wavelength and frequency of the new wave.
What could be done to stop the violent vibrations?
Advertisements
उत्तर
Wavelength = λ = 0.332 m
Time period = T = 10−3 s
Frequency = `1/"T"=1/10^-3` = 103 Hz.
Now the time period is decreased and is now 10−4 s.
∴ New frequency = `1/10^4` = 10−4 Hz,
Speed of sound, V = f × λ = 103 × 0.332
= 332 m/s
Since speed remains the same
∴ New wavelength, λ = `"V"/"f"=332/10^4` = 0.0332 m.
संबंधित प्रश्न
What is a soundboard ? Explain the working of a soundboard with the help of a labelled diagram.
What are mechanical waves?
Mention two properties of a wave, one property which varies and the other which remains constant when the wave passes from one medium to another.
Why is an echo not heard when the distance between the source of sound and reflection body is less than 10 m?
A radio signal, sent towards the surface of the moon, is received in 2.5 seconds. If the speed of the radio waves is 3 × 108 ms−1, find the distance of the moon from the earth.
Explain why, the ceilings of concert halls are curved.
Match the following:
| 1. | Stethoscope | a. | Repeated reflections |
| 2. | Echogram | b. | Multiple reflections |
| 3. | SONAR | c. | Ultrasonic waves |
| 4. | Reverberation | d. | Speed of underwater objects |
