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प्रश्न
A solution containing 34.2 g of sugar dissolved in 1 litre of water has an osmotic pressure of 2.522 atmospheres at 20°C. Calculate the value of gas constant, R.
संख्यात्मक
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उत्तर
Given: Mass of sugar = 34.2 g
Volume of solution = 1 L = 1 dm3
Osmotic pressure (π) = 2.522 atm
Temperature (T) = 20°C = 293 K
Molar mass of sugar (sucrose, C12H22O11) = 342 g/mol
Moles of sugar (n) = `"Mass"/"Molar mass"`
= `34.2/342`
= 0.1 mol
By using osmotic pressure formula,
`pi = (nRT)/V`
R = `(pi V)/(n T)`
R = `(2.522 xx 1)/(0.1 xx 293)`
R = `2.522/29.3`
R = 0.086 L atm mol−1 K−1
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