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प्रश्न
A solid metallic cone of radius 10 cm and height 12 cm is melted to form a wire of uniform area of cross-section 1 cm2. The length of wire formed is:
पर्याय
40 × π cm
4 × π m
400 × π m
2 × π m
MCQ
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उत्तर
4 × π m
Explanation:
Given,
A solid metallic cone of radius (r) 10 cm and height (h) 12 cm is melted to form a wire of uniform cross-section 1 cm2.
Let length of wire formed be l cm.
∴ Volume of cone = Volume of wire
\[\Rightarrow \frac{1}{3}\, \pi r^2 h = \text{Area of cross-section} \times \text{length}\]
\[\Rightarrow \frac{1}{3}\, \pi \times 10^2 \times 12 = 1 \times l\]
\[\Rightarrow l = 4 \times \pi \times 10^2\]
\[\Rightarrow l = 400\pi\ \text{cm}\]
\[\Rightarrow l = \frac{400\pi}{100}\ \text{m}\]
\[\Rightarrow l = 4 \times \pi\ \text{m}.\]
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