Question

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 90 cm. The period of oscillations of the sphere is ______. (g = 10 ms⁻²)

पर्याय

• (0.2) π

• (0.4) π

• (0.6) π

• (0.8) π

Answer 1

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 90 cm. The period of oscillations of the sphere is (0.6) π.

Explanation:

Given: Radius (R) = 90

g = 10 ms⁻²

Time period (T) = `2 pi sqrt (R/g)`

= `2 pi sqrt ((90 xx 10^-2)/10)`

= 2π × 0.3

= 0.6 π