Question

A simple machine displaces a load of 125 kgf through a distance of 0.30 m, when an effort of 12.5 kgf acts through a distance of 4.0 m. Answer the following question.

The velocity ratio of the machine is:

पर्याय

• 13.33

• 12.67

• 12.33

• 12.83

Answer 1

13.33

Explanation:

\[ \text{VR} = \frac{\text{Distance moved by effort}}{\text{Distance moved by load}} \]

\[= \frac{4.0}{0.30} \]

= 13.33