Question

A series LCR circuit is subjected to an AC signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is ______.

पर्याय

• 68 A

• 63 A

• 10 A

• 10 mA

Answer 1

A series LCR circuit is subjected to an AC signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is 10 A.

Explanation:

Given: f = 50 Hz

L = 10 mH = 10 × 10⁻³ H

V_L = 31.4 V

The resistance offered by an inductor in an AC circuit is given by:

X_L = 2 π f L

= 2 × 3.14 × 50 × (10 × 10⁻³)

= 3.14 × 10⁻²

= 3.14 Ω

The voltage across the inductor (V_L) is the product of the current (I) and the inductive reactance (X_L):

V_L = I . X_L

31.4 = 3.14 U

I = `31.4/3.14`

= 10 A