Question

A sector of 56° cut out from a circle contains area of 4.4 cm2. Find the radius of the circle

Answer 1

Angle subtended by sector at centre 𝜃 = 56°

Let radius be ‘x’ cm

Area of sector =`theta/360^@× pir^2`

=`56/360×22/7× r^2`

=`22/45`𝑟2

But area of sector = 4.4cm² =`44/10cm^2`

`22/45r^2 =44/10`

⇒ `r^2 =(45×44)/(22×10)`= 9

⇒ 𝑟 = `sqrt(9)`

= 3 𝑐𝑚

∴ radius (r) = 3cm