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प्रश्न
A sample space consists of 9 elementary outcomes e1, e2, ..., e9 whose probabilities are
P(e1) = P(e2) = 0.08, P(e3) = P(e4) = P(e5) = 0.1
P(e6) = P(e7) = 0.2, P(e8) = P(e9) = 0.07
Suppose A = {e1, e5, e8}, B = {e2, e5, e8, e9}
Calculate `P(barB)` from P (B), also calculate `P(barB)` directly from the elementary outcomes of `barB`
बेरीज
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उत्तर
Given that: S = {e1, e2, e3, e4, e5, e6, e7, e8, e9}
A = {e1, e5, e8} and B = {e2, e5, e8, e9}
P(e1) = P(e2) = 0.08
P(e3) = P(e4) = P(e5) = 0.1
P(e6) = P(e7) = 0.2, P(e8) = P(e9) = 0.07
`P(barB)` = 1 – P(B)
= 1 – 0.32
= 0.68
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