Question

A rectangle ABCD consists of 5 congruent rectangles as shown in the figure. If the area of the rectangle ABCD is 320 cm², find the dimensions of one small rectangle.

Answer 1

We are given:

• Rectangle ABCD is divided into 5 congruent rectangles
• Total area of rectangle ABCD = 320 cm²
• Need to find the dimensions of one small rectangle

Let the length of each small rectangle = L

Let the height of each small rectangle = H

Then:

• Total height of large rectangle = 5H
• Area of large rectangle = L × 5H = 320

So, L × 5H = 320

⇒ `LH = 320/5 = 64`

Now we need a factor pair of 64 such that:

• Length L = 16
• Height H = 4

So, each small rectangle is 4 cm × 16 cm.

Thus, one small rectangle measures 16 cm by 4 cm.