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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

A random variable X has the following probability distribution : x = x 0 1 2 3 7 P(X=x) 0 k 2k 2k 3k k2 2k2 7k2 + k Determine (i) k (ii) P(X> 6) (iii) P(0<X<3). - Mathematics and Statistics

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प्रश्न

A random variable X has the following probability distribution :

x = x 0 1 2 3       7
P(X=x) 0 k 2k 2k 3k k2 2k2 7k2 + k

Determine (i) k

(ii) P(X> 6)

(iii) P(0<X<3).

बेरीज
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उत्तर

Refer to the solution of Q. 8 of Exercise 7.1.

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पाठ 7: Probability Distributions - Miscellaneous Exercise 2 [पृष्ठ २४४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 7 Probability Distributions
Miscellaneous Exercise 2 | Q 8 | पृष्ठ २४४

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Solution:

Here, n = 4

p = probability of defective device = 10% = `10/100 = square`

∴ q = 1 - p = 1 - 0.1 = `square`

X ∼ B(4, 0.1)

 `P(X=x)=""^n"C"_x p^x q^(n-x)= ""^4"C"_x (0.1)^x (0.9)^(4 - x)`

P[At most one defective device] = P[X ≤ 1]

= P[X=0] + P[X=1]

= `square+square`

∴ P[X ≤ 1] = `square`


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