Question

A projectile is projected with a velocity of `(3hati + 4hatj)` m/s. The horizontal range of the projectile will be ______.

पर्याय

• 1.2 m

• 2.4 m

• 3.6 m

• 4.5 m

Answer 1

A projectile is projected with a velocity of `(3hati + 4hatj)` m/s. The horizontal range of the projectile will be 2.4 m.

Explanation:

Given, `u = 3hati + 4hatj`

∴ `u = |u| = sqrt(3^2 + 4^2)` ⇒ v = 5 m/s

From figure,

`sintheta = 4/5`

and `costheta = 3/5`

∴ R = `(u^2 sin2theta)/g = ("v"^2 . 2sintheta . costheta)/g`

= `(5 xx 5 xx 2 xx 4/5 xx 3/5)/10` = 2.4 m